I kind of miss my poetic language.
gotta figure it out once work done.
#random
Tuesday, April 16, 2013
Stress is good.
Just a quickies yawlsss.
Why stress good for you. Indeed why?
You can actually put all your problem aside and live the day happily ever after.
BUT NO! Please don't.
Stress is good for you. Literally, its good.
Focus realistically on your problem,
and set the solution for it.
It will practice your brain to be quicker.
Remember, problem can always become an opportunity.
.
Wednesday, April 10, 2013
Mix design references
Here is some mix design references;
M20 ( 1 : 2.48 : 3.55)
Cement : 320 Kg/ M3
20 mm Jelly : 683 Kg/ M3
12.5 mm Jelly : 455 Kg/ M3
River sand : 794 Kg/ M3
Total water : 176 Kg/ M3
Admixture : 0.7%
Fresh concrete density: 2430 Kg/ M3
Cement : 320 Kg/ M3
20 mm Jelly : 683 Kg/ M3
12.5 mm Jelly : 455 Kg/ M3
River sand : 794 Kg/ M3
Total water : 176 Kg/ M3
Admixture : 0.7%
Fresh concrete density: 2430 Kg/ M3
M25 ( 1 : 2.28 : 3.27)
Cement : 340 Kg/ M3
20 mm Jelly : 667 Kg/ M3
12.5 mm Jelly : 445 Kg/ M3
River sand : 775 Kg/ M3
Total water : 185 Kg/ M3
Admixture : 0.6%
Fresh concrete density: 2414 Kg/ M3
Note: sand 775 + 2% moisture, Water 185 -20.5 = 164 Liters,
Admixture = 0.5% is 100ml
M30 ( 1 : 2 : 2.87)
Cement : 380 Kg/ M3
20 mm Jelly : 654 Kg/ M3
12.5 mm Jelly : 436 Kg/ M3
River sand : 760 Kg/ M3
Total water : 187 Kg/ M3
Admixture : 0.7%
Fresh concrete density: 2420 Kg/ M3
Note: Sand = 760 Kg with 2% moisture (170.80+15.20)
M35 ( 1 : 1.79 : 2.57)
Cement : 410 Kg/ M3
20 mm Jelly : 632 Kg/ M3
12.5 mm Jelly : 421 Kg/ M3
River sand : 735 Kg/ M3
Total water : 200 Kg/ M3
Admixture : 0.7%
Fresh concrete density: 2400 Kg/ M3
Note: sand = 735 + 2%, Water = 200- 14.7 = 185.30,
Admixture = 0.7%
Cement : 340 Kg/ M3
20 mm Jelly : 667 Kg/ M3
12.5 mm Jelly : 445 Kg/ M3
River sand : 775 Kg/ M3
Total water : 185 Kg/ M3
Admixture : 0.6%
Fresh concrete density: 2414 Kg/ M3
Note: sand 775 + 2% moisture, Water 185 -20.5 = 164 Liters,
Admixture = 0.5% is 100ml
M30 ( 1 : 2 : 2.87)
Cement : 380 Kg/ M3
20 mm Jelly : 654 Kg/ M3
12.5 mm Jelly : 436 Kg/ M3
River sand : 760 Kg/ M3
Total water : 187 Kg/ M3
Admixture : 0.7%
Fresh concrete density: 2420 Kg/ M3
Note: Sand = 760 Kg with 2% moisture (170.80+15.20)
M35 ( 1 : 1.79 : 2.57)
Cement : 410 Kg/ M3
20 mm Jelly : 632 Kg/ M3
12.5 mm Jelly : 421 Kg/ M3
River sand : 735 Kg/ M3
Total water : 200 Kg/ M3
Admixture : 0.7%
Fresh concrete density: 2400 Kg/ M3
Note: sand = 735 + 2%, Water = 200- 14.7 = 185.30,
Admixture = 0.7%
concrete weigth calculation
The question
"nina, saiz apa yang kita perlu utk concrete m25 jadi 20kg?"
(Nina, on what size needed for the m25 concrete to become 20kg?)
So here is the do-how;
let say the concrete will be in rectangular shape.
Method 1
1) find the volume of the concrete.
let say we assume 6" x 6" x 6" ;
in this case assume every size that you feel near to the weight value.
2) volume of a rectangular : width x height x thickness = Ym^3
then the density of the concrete. (refer the mix design reference)
For the gred m25, we have 2414kg/m^3.
3) Then use this formula to find the weight in kg = density x volume.
Method 2
1) From the handout, we have know the density.
Given weight = 20 kg
Given density = 2414
so find the volume, v = 20/2414 = ??
2) since we have know the volume, now assume the size of the concrete, depend on your design.
tips : Method 1 is easier.
tips : check next post for the mix design references.
"nina, saiz apa yang kita perlu utk concrete m25 jadi 20kg?"
(Nina, on what size needed for the m25 concrete to become 20kg?)
So here is the do-how;
let say the concrete will be in rectangular shape.
Method 1
1) find the volume of the concrete.
let say we assume 6" x 6" x 6" ;
in this case assume every size that you feel near to the weight value.
2) volume of a rectangular : width x height x thickness = Ym^3
then the density of the concrete. (refer the mix design reference)
For the gred m25, we have 2414kg/m^3.
3) Then use this formula to find the weight in kg = density x volume.
Method 2
1) From the handout, we have know the density.
Given weight = 20 kg
Given density = 2414
so find the volume, v = 20/2414 = ??
2) since we have know the volume, now assume the size of the concrete, depend on your design.
tips : Method 1 is easier.
tips : check next post for the mix design references.
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